Ingress 13 Archetypes 08: Omniscient
好无聊啊
About 13 Archetypes
这是一个长达 13 周的解谜挑战,北京时间 12 月 10 日凌晨 01:00 起, Niantic 会在其论坛上发布一个谜题,然后让玩家解谜,结果会是一个 Passcode ,兑换后可获得 Media 一个。
Omniscient
1 | <code font size="n2esab" pixel width="4" pixel depth="^3">e4a4646494652374c4949565d423459494a5c454d4753574b4a544841565238594a5c464d4652374b4a56565f4253523b4a5c47555353555b4536544b4652385e494234554653574f425c465f42535237464c47455d4b485b45344849433b475e4a435747565357494a43464d4234554e4e4c47555453555b443d3d3d3d3d3d3</code> |
Decode
Infomation
n2esab
4^3=64
e4a4646494652374c4949565d423459494a5c454d4753574b4a544841565238594a5c464d4652374b4a56565f4253523b4a5c47555353555b4536544b4652385e494234554653574f425c465f42535237464c47455d4b485b45344849433b475e4a435747565357494a43464d4234554e4e4c47555453555b443d3d3d3d3d3d3
Solution
翻转字符串 n2esab
得到 base2n
,说明本次谜题和 Base16、Base32、Base64 编码方法有关。
将上述一长串字符串翻转后可得:
1 | 3d3d3d3d3d3d344b55535455574c4e4e4554324d46434a494753565747534a4e574b33494844354b584b4d55474c46473253524f564c524f475356455432494e5832564b4456354b55535355574c5a4b3253524f56565a4b4732564d464c5a495832565148445a4b4753574d454c5a494954324d5659494c4732564946464a4e |
按照 ASCII 转换为对应的字符,即为:
1 | ======4KUSTUWLNNET2MFCJIGSVWGSJNWK3IHD5KXKMUGLFG2SROVLROGSVET2INX2VKDV5KUSSUWLZK2SROVVZKG2VMFLZIX2VQHDZKGSWMELZIIT2MVYILG2VIFFJN |
再翻转回来:
1 | NJFFIV2GLIYVM2TIIZLEMWSGKZDHQV2XIZLFMV2GKZVVORS2KZLWUSSUK5VDKV2XNI2TEVSGORLVORS2GFLGUMKXK5DHI3KWNJSGWVSGIJCFM2TENNLWUTSUK4====== |
所有字母均为大写,则按照 Base32 来解码,即为:
1 | jJTWFZ1VjhFVFZFVFxWWFVVWFVkWFZVWjJTWj5WWj52VFtWWFZ1Vj1WWFtmVjdkVFBDVjdkWjNTW |
再翻转一次:
1 | WTNjWkdjVDBFVkdjVmtFWW1jV1ZFWWtFV25jWW5jWTJjWVZFWkVFWVVFWWxFVFZFVFhjV1ZFWTJj |
按照 Base64 解码:
1 | Y3cZGcT0EVGcVkEYmcWVEYkEWncYncY2cYVEZEEYUEYlETVETXcWVEY2c |
每 3 位后补一个 =
后,按照 Base64 每 4 位分别解码:
1 | cwdgOATgVAbgYQbAZwbwcgaQdAaAbQMQMwYQcg |
每 2 位后补两个 =
后,按照 Base64 每 4 位分别解码:
1 | sv8NTnalgorithm13ar |
兑换获得Media一枚
真的很无聊 (:зゝ∠)